(x+y)/2 = 7
xy/3 = 16
y=48/x
x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) = 0
x and y are 6 and 8
half of the sum of two number is 7,while one third of their product is 16,find the numbers
6 answers
Thanks
Not great
x+y)/2 = 7
xy/3 = 16
y=48/x
x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) =0
The numbers are 6 and 8
That's all
xy/3 = 16
y=48/x
x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) =0
The numbers are 6 and 8
That's all
thanks for solving my question
1.A ,2.B