half of the sum of two number is 7,while one third of their product is 16,find the numbers

Answer 1

(x+y)/2 = 7
xy/3 = 16

y=48/x

x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) = 0

x and y are 6 and 8

Answer 2

Thanks

Answer 3

Not great

Answer 4

x+y)/2 = 7
xy/3 = 16

y=48/x

x+48/x = 14
x^2-14x+48 = 0
(x-6)(x-8) =0
The numbers are 6 and 8
That's all

Answer 5

thanks for solving my question

Answer 6

1.A ,2.B