Haley is standing in the base path between second and third base when she fields the ball.%C2%A0 She is 24 feet from second base and needs to make the throw to first base.%C2%A0 Assuming the field is square, how far does she need to throw the ball?%C2%A0 Round your answer to the nearest tenth.

Answer 1

To find the distance Haley needs to throw the ball, we can use the Pythagorean theorem.

Let's assume the distance she needs to throw is x.

Since the field is square, the distance from second base to first base is the same as the distance from second base to third base, which is 24 feet.

So, we can form a right-angled triangle with the distance from second base to third base as the base, the distance from second base to first base as the hypotenuse, and the distance Haley needs to throw the ball as the height.

Using the Pythagorean theorem, we have:

x^2 = 24^2 + 24^2
x^2 = 576 + 576
x^2 = 1152
x = √1152 ≈ 33.94

Therefore, Haley needs to throw the ball approximately 33.9 feet.