25cm^3 * 6mol/L = 0.15 moles of HA
45cm^3 * 3mol/L = 0.135 moles of HB
That will leave 0.015 moles of HA
Now you can get the pH of that.
HA and HB are two strong monobasic acids. 25cm3 of 6moldm-3 Ha is mixed with 45cm3 of 3moldm-3 HB. What is the H+ concentration in moldm-3 in the resting solution
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