The reaction you've written appears to be a neutralization reaction between phosphoric acid (H₃PO₄) and calcium hydroxide (Ca(OH)₂). The products of this reaction include calcium phosphate (Ca₃(PO₄)₂) and water (H₂O).
To balance the equation, let's first write the unbalanced form:
\[ \text{H}_3\text{PO}_4 + \text{Ca(OH)}_2 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + \text{H}_2\text{O} \]
To balance this reaction, we need to follow these steps:
- Identify the number of each type of atom on both sides.
- Balance the calcium (Ca) atoms: Calcium phosphate has 3 calcium atoms, meaning we need 3 calcium hydroxide molecules on the reactant side.
- Balance the phosphate (PO₄) counts: Calcium phosphate has 2 phosphate groups, thus we need 2 phosphoric acid molecules.
- Balance the hydrogen (H) and oxygen (O) atoms.
The balanced equation would look like this:
\[ 2 \text{H}_3\text{PO}_4 + 3 \text{Ca(OH)}_2 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + 6 \text{H}_2\text{O} \]
Balanced Reaction:
\[ 2 \text{H}_3\text{PO}_4 + 3 \text{Ca(OH)}_2 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + 6 \text{H}_2\text{O} \]
Summary
- 2 molecules of phosphoric acid react with 3 molecules of calcium hydroxide to form 1 molecule of calcium phosphate and 6 molecules of water.
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