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_H3PO4(aq) + _Ca(s) → Ca(PO4)2 (aq) + _H2(8)
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The balanced chemical equation for the reaction is:
2H3PO4(aq) + 3Ca(s) → Ca3(PO4)2(aq) + 3H2(g)
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_H3PO4+_KOH->_K3PO4+_H2O
if 49.0 g of H3PO4 is reacted with excess KOH, determind the percent yield of K3PO4 if you produce 49.0
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