H2(g) + 12(g) + 2H1(g)

A student makes the following statements:
- Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H2 and product Hi.
- Iodine is in Group VIlA, so it has an oxidation number of -1 in both the reactant 12 and
product HI.
- Neither hydrogen nor iodine changes oxidation states, so the reaction is not a redox reaction.

In three to five sentences, describe the mistake that the student made, and determine whether or not the reaction is a redox reaction. Explain your answer.

1 answer

It would have been SOOOOOO much easier if you had written what you do (or don't) know about this.
First the equation is not written properly. It should be
H2(g) + I2(g) = 2HI(g) (Note the I and not 1. Note = sign not +)
H and I don't always have the same oxidation state. On the left H is 0 and so is I. On the right H is +1 and I is -1.
The fact that BOTH H and I changed oxidation state means it was a redox reaction.
Now you can put all of that into sentence form. I'm a chemist and not a writer.
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