h(x)=(2-2x^2)/-2

Question

h(-2)

I get (-2-2(-2)^2)/-2
(-2-2(4)/-2
6/-2=-3

h(-2)=-3

Answer 1

h(x) = (2 - 2x^2)/-2

h(-2) = (2 - 2[2^2])/-2
h(-2) = (2 - 2[4])/-2
h(-2) = (2 - 8)/-2
h(-2) = -6/-2
h(-2) = 3

This is what I get from what the original function was as typed and plugging -2 into it.

Answer 2

I see what I did, I put a neg in front when it should have been and carried it through. Thanks