To find the vertex of the quadratic function h(t)=-16t^2+150t+22, we can use the formula for the x-coordinate of the vertex, which is given by the formula t = -b/2a, where a = -16 and b = 150 in this case.
t = -b/2a = -150/(2*(-16)) = -150/(-32) = 4.6875
To find the corresponding y-coordinate, we substitute t = 4.6875 into the function:
h(4.6875) = -16*(4.6875)^2 + 150*(4.6875) + 22 = 682.03125
Therefore, the vertex of the quadratic function is (4.6875, 682.03125).
h(t)=-16t^2+150t+22 find the vertex.
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