h\left(t\right)=-16t^{2}-64t

Answer 1

The function h(t) can be rewritten as:

h(t) = -16t^2 - 64t

This function represents the height of an object above the ground (in feet) as a function of time t (in seconds) when the object is thrown with an initial velocity of -64 feet per second. The -16t^2 term represents the effect of gravity on the object's height, causing it to decrease over time, while the -64t term represents the initial downward velocity of the object.