(h+j/h-j)-²

Answer 1

To simplify the expression \((\frac{h+j}{h-j})^{-2}\), we can follow these steps:

1. First recognize that \((x)^{-2} = \frac{1}{x^2}\). So, \[ \left(\frac{h+j}{h-j}\right)^{-2} = \frac{1}{\left(\frac{h+j}{h-j}\right)^2} \]

2. Next, we can express the denominator squared: \[ \left(\frac{h+j}{h-j}\right)^2 = \frac{(h+j)^2}{(h-j)^2} \]

3. Therefore, the expression becomes: \[ \frac{1}{\frac{(h+j)^2}{(h-j)^2}} = \frac{(h-j)^2}{(h+j)^2} \]

So the simplified form of the original expression \((\frac{h+j}{h-j})^{-2}\) is: \[ \frac{(h-j)^2}{(h+j)^2} \]