Let the width of the terrace be \( w \) yards. Since the length is 2 yards greater than the width, we can express the length as \( l = w + 2 \) yards.
The perimeter \( P \) of a rectangle is given by the formula:
\[ P = 2l + 2w \]
Greg has 24 yards of material for the fence, so:
\[ 2l + 2w = 24 \]
We can simplify this equation:
\[ l + w = 12 \]
Now, substituting \( l \) with \( w + 2 \):
\[ (w + 2) + w = 12 \]
Combining like terms, we have:
\[ 2w + 2 = 12 \]
Subtracting 2 from both sides:
\[ 2w = 10 \]
Dividing by 2:
\[ w = 5 \]
Now, we can find the length \( l \):
\[ l = w + 2 = 5 + 2 = 7 \]
Thus, the dimensions of the terrace are:
- Width: 5 yards
- Length: 7 yards
Therefore, the length of the terrace should be 7 yards.
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