Gravity is pulling downward on a 20.0kg block resting on a 15 degree incline. What is the magnitude of the force component parallel to the surface (hint: how to turn 20.0kg into force)?
3 answers
parallel down=m*g*cosTheta
parallel down=m*g*SinTheta
correction here, sine, not cosine.
the friction on the plane down the plane is mu*mg*CosTheta
correction here, sine, not cosine.
the friction on the plane down the plane is mu*mg*CosTheta
Oh wow thanks! I was wondering if you could give me an explanation as to how you found the solution if that isn't too much to ask
2 answers