To analyze the piecewise function \( f(x) \):
\[ f(x) = \begin{cases} x + 5 & \text{if } x \leq -2 \ 2x + 3 & \text{if } x > -2 \end{cases} \]
1. Finding the y-values at the endpoint \( x = -2 \):
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For \( x \leq -2 \) (specifically at \( x = -2 \)): \[ f(-2) = -2 + 5 = 3 \]
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For \( x > -2 \) (specifically at \( x = -2 \)): \[ \text{This piece of the function does not include } x = -2. \] However, we can find \( f(x) \) approaching \( -2 \) from the right: \[ \lim_{x \to -2^+} f(x) = 2(-2) + 3 = -4 + 3 = -1 \]
2. Analyzing the endpoints:
- At \( x = -2\):
- The function value is \( 3 \) (from the left side).
- The limit from the right approaches \( -1 \).
This means that the graph will have an open endpoint at the point \( (-2, -1) \), because the value at \( x = -2 \) does not include \( -2 \) in the second piece of the piecewise function (which only includes values greater than \( -2 \)).
Conclusion:
Answer: Yes, at \( (-2, 3) \) and \( (-2, -1) \).
Final Response:
Yes, at (−2,3) and (−2,−1).