Graphs of Quadratic Equations Quick Check

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Question
Use the image to answer the question.

A parabola is graphed on a coordinate plane. The x-axis ranges from negative 14 to 1 in increments of 1. The y-axis ranges from negative 2 to 6 in increments of 1.

Identify the vertex on the graph.

(1 point)
Responses

x=−11
x equals negative 11

(−12,0)
left parenthesis negative 12 comma 0 right parenthesis

(−10,0)
left parenthesis negative 10 comma 0 right parenthesis

(−11,−1)
left parenthesis negative 11 comma negative 1 right parenthesis
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1 answer

To identify the vertex of the parabola, we need to know the highest or lowest point of the graph (depending on whether it opens upwards or downwards).

The vertex is usually given in the format \((x, y)\) where \(x\) is the horizontal coordinate and \(y\) is the vertical coordinate.

Based on the options you've provided:

  1. \(x = -11\) - This is not a point and thus cannot be the vertex.
  2. \((-12, 0)\) - This point is valid, but we need to verify if it is the vertex.
  3. \((-10, 0)\) - This point is valid, but similarly needs verification.
  4. \((-11, -1)\) - This point is also valid and could potentially be the vertex.

To determine the vertex, it would be best to check the graphical representation for the highest or lowest point (the peak or trough of the parabola). If you see the vertex at a certain point visually or from a description, you can confirm which option is accurate.

If you do not have access to the graph at this moment, based on common characteristics of parabolas, the vertex tends to be either on the line of symmetry or the lowest/highest point based on the parabola's orientation.

If you could describe the graph further or if you have any additional details (like where the parabola opens), I can help you determine which point is the vertex you should select.