To find the high or low point of the parabola represented by the quadratic equation \( y = -6x^2 + 3x + 8 \), we need to determine whether the vertex of the parabola is a maximum (high point) or minimum (low point).
The vertex \( x \)-coordinate for a quadratic equation in the form \( y = ax^2 + bx + c \) is given by the formula:
\[ x = -\frac{b}{2a} \]
In this equation:
- \( a = -6 \)
- \( b = 3 \)
Calculating the \( x \)-coordinate of the vertex:
\[ x = -\frac{3}{2(-6)} = -\frac{3}{-12} = \frac{1}{4} = 0.25 \]
Next, we substitute \( x = 0.25 \) back into the equation to find the corresponding \( y \)-value:
\[ y = -6(0.25)^2 + 3(0.25) + 8 \]
Calculating each term:
- \( (0.25)^2 = 0.0625 \)
- \( -6 \cdot 0.0625 = -0.375 \)
- \( 3 \cdot 0.25 = 0.75 \)
Putting it all together:
\[ y = -0.375 + 0.75 + 8 = 0.375 + 8 = 8.375 \]
Thus, the vertex is \( (0.25, 8.375) \), and since \( a < 0 \) (the parabola opens downward), this point is the high point of the parabola.
Based on the available choices, the correct response is:
(0.25, 8.375) is the high point on the parabola.