Graphing Linear Equations Unit Test

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Question
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A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis negative 1 comma 2 right parenthesis. Point B is plotted at left parenthesis 0 comma negative 1 right parenthesis.

Write the equation of the line in slope-intercept form.

(1 point)
y=
x+(
)
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Answer 1

To find the equation of the line in slope-intercept form, we first need to find the slope of the line using the two given points (A and B).

slope = (y2 - y1) / (x2 - x1)
slope = (-1 - 2) / (0 - (-1))
slope = (-3) / (1)
slope = -3

Next, we choose one of the given points to plug into the equation y = mx + b in order to solve for the y-intercept (b). Let's choose point A (-1, 2):

2 = -3(-1) + b
2 = 3 + b
b = -1

Therefore, the equation of the line in slope-intercept form is:

y = -3x - 1