Graphing Equations Practice

Question

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Question
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An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows on both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma negative 2 right parenthesis and left parenthesis 3 comma 0 right parenthesis.

Write the equation of the line in slope-intercept form.

(1 point)

Answer 1

To find the equation of the line in slope-intercept form, we need to calculate the slope (m) and the y-intercept (b).

First, calculate the slope using the two points given: (0, -2) and (3, 0).
m = (y2 - y1) / (x2 - x1)
m = (0 - (-2)) / (3 - 0)
m = 2 / 3

Next, we can use one of the points to find the y-intercept (b). Let's use (0, -2).
y = mx + b
-2 = (2/3)(0) + b
-2 = b

Therefore, the equation of the line in slope-intercept form is:
y = (2/3)x - 2