Graph Y < 2X + 2. First, we graph the
boundary line which always uses an equal sign: Y = 2X + 2. Since there's no = sign in the inequality, the boundary line should be a dotted line.
Select 2 or 3 convenient points:
(0 , 2) , (-1 , 0) , (2 , 6). The 1st 2 points are the Y and X - Intercepts.
The points on the dotted line should
not satisfy the inequality. Let's test
the 1st point: 2 < 2*0 + 2, 2 < 2 is
not a true statement. Therefore, the
point does not satisfy the inequality.
The solution is either all points below the line or all points above
the line. Let's test a point below
the line: Try (0 , 0).0 < 2*0 + 2,
0 < 2 is a true statement. So ALL
points below the line are part of the
solution and should satisfy the in-
equality. ALL of the area below the
line is normally shaded.
Graph y<2x+2
1 answer
1 answer