To determine the y-intercepts of the functions \( f(x) = \sqrt{x - 2} \) and \( g(x) = \sqrt{2 - x} \), we evaluate each function at \( x = 0 \).
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For \( f(x) = \sqrt{x - 2} \): \[ f(0) = \sqrt{0 - 2} = \sqrt{-2} \] This expression is undefined because the square root of a negative number is not real. Therefore, \( f(x) \) does not have a y-intercept.
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For \( g(x) = \sqrt{2 - x} \): \[ g(0) = \sqrt{2 - 0} = \sqrt{2} \] This expression is defined and gives a real value, \( \sqrt{2} \). Therefore, \( g(x) \) has a y-intercept.
Since only \( g(x) \) has a y-intercept, the answer is:
g(x)