Asked by cool
Graph the polynomial f(x)=(x+6)(x+4)^2 (x+2)^3(x-3) (x-5)
a) Describe the interval notation the set of all x such that f(x)>0.
b) Graph on a number line the set of all x such that f(x) > 0.
c)Describe in interval notation the set of all x such that f(x) ≥ 0.
d).Graph on a number line the set of all x such that f(x) ≥ 0.
a) Describe the interval notation the set of all x such that f(x)>0.
b) Graph on a number line the set of all x such that f(x) > 0.
c)Describe in interval notation the set of all x such that f(x) ≥ 0.
d).Graph on a number line the set of all x such that f(x) ≥ 0.
Answers
Answered by
Steve
These interval questions are easy.
f(x) is a 8th degree polynomial with positive first coefficient, so its end behavior on both ends is that it rises up to +infinity.
So, look at the smallest and largest roots: -6 and 5
f(x) > 0 for x < -6 and x > 5
So, what about in between? The trick here is to recall that
at a root of odd order, the graph crosses the x-axis (think x or x^3)
at a root of even order, the graph just touches the x-axis and then goes back the way it came. (think x^2)
So, the graph of f(x) crosses the x-axis at x = -6,-2,3,5
It just touches the x-axis at x = -4
So, looking at the x-axis, we have
<-- +++ (-6) --- (-4) --- (-2) +++ (3) --- (5) +++ -->
f(x) is a 8th degree polynomial with positive first coefficient, so its end behavior on both ends is that it rises up to +infinity.
So, look at the smallest and largest roots: -6 and 5
f(x) > 0 for x < -6 and x > 5
So, what about in between? The trick here is to recall that
at a root of odd order, the graph crosses the x-axis (think x or x^3)
at a root of even order, the graph just touches the x-axis and then goes back the way it came. (think x^2)
So, the graph of f(x) crosses the x-axis at x = -6,-2,3,5
It just touches the x-axis at x = -4
So, looking at the x-axis, we have
<-- +++ (-6) --- (-4) --- (-2) +++ (3) --- (5) +++ -->
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.