To analyze the piecewise function \( f(x) \):
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Function Definition:
- For \( x \leq -2 \), \( f(x) = x + 5 \)
- For \( x > -2 \), \( f(x) = 2x + 3 \)
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Finding the function values at \( x = -2 \):
- For \( x = -2 \):
- If \( x \leq -2 \), \( f(-2) = -2 + 5 = 3 \)
- If \( x > -2 \), \( f(-2) \) is not defined.
- For \( x = -2 \):
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Endpoints:
- At \( x = -2 \), the function has a value \( f(-2) = 3 \) (from the first piece).
- The next piece, \( f(x) = 2x + 3 \), will not include the value at \( x = -2 \) since it only applies for \( x > -2 \).
Therefore, there is an open endpoint at \( (-2, 3) \) because while it is included in the first piece, the second piece does not include this point.
Conclusion
Yes, there is an open endpoint at \( (-2, 3) \).
The correct response is: Yes, at (−2, 3).