Since the graph of a linear equation is a straight line, we can plot two points and then draw the line passing through them.
Let's choose x = 0 and x = 3.
When x = 0:
y = 2(0) - 3
y = -3
The point (0, -3) is on the graph.
When x = 3:
y = 2(3) - 3
y = 6 - 3
y = 3
The point (3, 3) is on the graph.
Plot these two points and draw a straight line passing through them.
The graph of the linear equation y = 2x - 3 is a line that starts at (0, -3) and passes through (3, 3).
Graph the linear equation y=2x−3 .(1 point)
3 answers
try again
I'm sorry for the mistake.
To graph the linear equation y = 2x - 3, we can use the slope-intercept form of the equation, which is y = mx + b, where m is the slope and b is the y-intercept.
In this case, the slope is 2 and the y-intercept is -3.
Plot the point (0, -3) as the y-intercept.
Use the slope to find another point, which is rise 2 and run 1 from the y-intercept.
Plot these two points and draw a straight line connecting them.
The graph of the linear equation y = 2x - 3 is a line that passes through the points (0, -3) and (1, -1).
To graph the linear equation y = 2x - 3, we can use the slope-intercept form of the equation, which is y = mx + b, where m is the slope and b is the y-intercept.
In this case, the slope is 2 and the y-intercept is -3.
Plot the point (0, -3) as the y-intercept.
Use the slope to find another point, which is rise 2 and run 1 from the y-intercept.
Plot these two points and draw a straight line connecting them.
The graph of the linear equation y = 2x - 3 is a line that passes through the points (0, -3) and (1, -1).
1 answer