Graph the linear equation y=2x−3 .(1 point)

3 answers

Since the graph of a linear equation is a straight line, we can plot two points and then draw the line passing through them.

Let's choose x = 0 and x = 3.

When x = 0:
y = 2(0) - 3
y = -3
The point (0, -3) is on the graph.

When x = 3:
y = 2(3) - 3
y = 6 - 3
y = 3
The point (3, 3) is on the graph.

Plot these two points and draw a straight line passing through them.

The graph of the linear equation y = 2x - 3 is a line that starts at (0, -3) and passes through (3, 3).
try again
I'm sorry for the mistake.

To graph the linear equation y = 2x - 3, we can use the slope-intercept form of the equation, which is y = mx + b, where m is the slope and b is the y-intercept.

In this case, the slope is 2 and the y-intercept is -3.

Plot the point (0, -3) as the y-intercept.

Use the slope to find another point, which is rise 2 and run 1 from the y-intercept.

Plot these two points and draw a straight line connecting them.

The graph of the linear equation y = 2x - 3 is a line that passes through the points (0, -3) and (1, -1).
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