Graph the linear equation y=2/3x−1 . (1 point)

Answer 1

To graph the linear equation y = 2/3x - 1, we can start by plotting some points on the coordinate plane.

Let's choose some values of x and find the corresponding values of y.

When x = -3:
y = (2/3)(-3) - 1
y = -2 - 1
y = -3

So one point on the graph is (-3, -3).

When x = 0:
y = (2/3)(0) - 1
y = -1

So another point on the graph is (0, -1).

When x = 3:
y = (2/3)(3) - 1
y = 2 - 1
y = 1

So another point on the graph is (3, 1).

Using these points, we can plot them on the coordinate plane and draw a straight line through them.

Here is the graph:

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| . (3, 1)
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| . (0, -1)
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| (-3, -3)
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Answer 2

Graph the linear equation y=−3x+2 .(1 point)

Answer 3

To graph the linear equation y = -3x + 2, we can start by plotting some points on the coordinate plane.

Let's choose some values of x and find the corresponding values of y.

When x = -2:
y = -3(-2) + 2
y = 6 + 2
y = 8

So one point on the graph is (-2, 8).

When x = 0:
y = -3(0) + 2
y = 2

So another point on the graph is (0, 2).

When x = 2:
y = -3(2) + 2
y = -6 + 2
y = -4

So another point on the graph is (2, -4).

Using these points, we can plot them on the coordinate plane and draw a straight line through them.

Here is the graph:

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. | . (2, -4)
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| . (0, 2)
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| . (-2, 8)
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