To graph the linear equation y = 2/3x - 1, we can start by plotting some points on the coordinate plane.
Let's choose some values of x and find the corresponding values of y.
When x = -3:
y = (2/3)(-3) - 1
y = -2 - 1
y = -3
So one point on the graph is (-3, -3).
When x = 0:
y = (2/3)(0) - 1
y = -1
So another point on the graph is (0, -1).
When x = 3:
y = (2/3)(3) - 1
y = 2 - 1
y = 1
So another point on the graph is (3, 1).
Using these points, we can plot them on the coordinate plane and draw a straight line through them.
Here is the graph:
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| . (3, 1)
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| . (0, -1)
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| (-3, -3)
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Graph the linear equation y=2/3x−1 . (1 point)
3 answers
Graph the linear equation y=−3x+2 .(1 point)
To graph the linear equation y = -3x + 2, we can start by plotting some points on the coordinate plane.
Let's choose some values of x and find the corresponding values of y.
When x = -2:
y = -3(-2) + 2
y = 6 + 2
y = 8
So one point on the graph is (-2, 8).
When x = 0:
y = -3(0) + 2
y = 2
So another point on the graph is (0, 2).
When x = 2:
y = -3(2) + 2
y = -6 + 2
y = -4
So another point on the graph is (2, -4).
Using these points, we can plot them on the coordinate plane and draw a straight line through them.
Here is the graph:
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. | . (2, -4)
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| . (0, 2)
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| . (-2, 8)
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Let's choose some values of x and find the corresponding values of y.
When x = -2:
y = -3(-2) + 2
y = 6 + 2
y = 8
So one point on the graph is (-2, 8).
When x = 0:
y = -3(0) + 2
y = 2
So another point on the graph is (0, 2).
When x = 2:
y = -3(2) + 2
y = -6 + 2
y = -4
So another point on the graph is (2, -4).
Using these points, we can plot them on the coordinate plane and draw a straight line through them.
Here is the graph:
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. | . (2, -4)
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--------|--------------
| . (0, 2)
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| . (-2, 8)
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