To graph the linear equation \( y = \frac{2}{3}x - 1 \), we can determine specific points by substituting different x-values into the equation and then identifying the corresponding y-values.
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Finding Points:
- Let’s find the y-intercept (when \( x = 0 \)): \[ y = \frac{2}{3}(0) - 1 = -1 \quad \Rightarrow \quad (0, -1) \]
- Let’s find the point when \( x = 3 \): \[ y = \frac{2}{3}(3) - 1 = 2 - 1 = 1 \quad \Rightarrow \quad (3, 1) \]
- Let’s find the point when \( x = -3 \): \[ y = \frac{2}{3}(-3) - 1 = -2 - 1 = -3 \quad \Rightarrow \quad (-3, -3) \]
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Plotting the Points:
- The points we have are \( (0, -1) \), \( (3, 1) \), and \( (-3, -3) \).
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Drawing the Line:
- Once the points are plotted, draw a straight line through these points extending in both directions with arrows at the ends.
From your options, the correct graph should pass through the points \( (0, -1) \) and \( (3, 1) \). Please select the illustration that reflects these points correctly.