Graph the linear equation. 𝑦 = 1 3 𝑥 − 1 R. 𝑚 = 1 2 𝑎𝑛𝑑 𝑏 = −1 S. 𝑚 = 1 3 𝑎𝑛𝑑 𝑏 = −1 T. 𝑚 = 1 3 𝑎𝑛𝑑 𝑏 = 1

Answer 1

To graph the linear equations, we will use the slope-intercept form 𝑦 = 𝑚𝑥 + 𝑏, where 𝑚 is the slope and 𝑏 is the y-intercept.

R. 𝑚 = 1 2 and 𝑏 = -1

The equation can be rewritten as 𝑦 = 1/2𝑥 - 1.

Plot the y-intercept at (0, -1) and use the slope of 1/2 to find another point. For example, if we move up 1 unit and right 2 units, we get the point (2, 0). Connect the two points with a straight line.

S. 𝑚 = 1 3 and 𝑏 = -1

The equation can be rewritten as 𝑦 = 1/3𝑥 - 1.

Plot the y-intercept at (0, -1) and use the slope of 1/3 to find another point. For example, if we move up 1 unit and right 3 units, we get the point (3, 0). Connect the two points with a straight line.

T. 𝑚 = 1 3 and 𝑏 = 1

The equation can be rewritten as 𝑦 = 1/3𝑥 + 1.

Plot the y-intercept at (0, 1) and use the slope of 1/3 to find another point. For example, if we move up 1 unit and right 3 units, we get the point (3, 2). Connect the two points with a straight line.

Now you have the graphs of the three linear equations R, S, and T.

Answer 2

only one answer

Answer 3

Apologies for the confusion. Let's graph the linear equation 𝑦 = 1/3𝑥 − 1.

To graph this equation, we need to plot the y-intercept at -1 and use the slope of 1/3 to find another point. The slope of 1/3 means that for every 1 unit we move to the right, we need to move up 1/3 unit.

Plot the y-intercept at (0, -1) and then move up 1 unit and right 3 units to get the point (3, 0). Connect these two points with a straight line.

Therefore, the graph of the linear equation 𝑦 = 1/3𝑥 − 1 is a line passing through the points (0, -1) and (3, 0).