To find the two points on the line, we can use the point-slope form of a linear equation, which is given by:
y - y1 = m(x - x1)
Where (x1, y1) is the given point, and m is the slope.
In this case, the given point is (1, -1), and the slope is 3/2. Plugging these values into the equation, we have:
y - (-1) = (3/2)(x - 1)
Simplifying the equation, we have:
y + 1 = (3/2)(x - 1)
Expanding the term (3/2)(x - 1), we get:
y + 1 = (3/2)x - 3/2
Subtracting 1 from both sides of the equation, we have:
y = (3/2)x - 3/2 - 1
Simplifying, we have:
y = (3/2)x - 3/2 - 2/2
Combining like terms, we get:
y = (3/2)x - 5/2
Now we can graph the line using the equation y = (3/2)x - 5/2. The graph will be a straight line passing through the point (1, -1) with a slope of 3/2.
To find two points on the line, we can choose any x-values, substitute them into the equation, and calculate the corresponding y-values.
For example, let's choose x = 0:
y = (3/2)(0) - 5/2 = -5/2
So the point (0, -5/2) lies on the line.
Let's choose another x-value, x = 2:
y = (3/2)(2) - 5/2 = 1/2
So the point (2, 1/2) also lies on the line.
Thus, the two points on the line are (0, -5/2) and (2, 1/2).
Graph the line with the given point and slope.
The line through (1, -1) with slope 3/2. Find the two points.
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