To graph the line with the given point and slope, we can use the point-slope form of a linear equation.
The point-slope form of a linear equation is y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.
In this case, the given point is (-1, 0) and the slope is 2/3.
Using the point-slope form, the equation of the line is y - 0 = (2/3)(x - (-1)).
Simplifying the equation, we get y = (2/3)(x + 1).
To graph the line, we can plot the given point (-1, 0) and then find additional points on the line using the slope.
Let's choose x = -4 as an additional point on the line:
y = (2/3)(-4 + 1)
y = (2/3)(-3)
y = -2
So, we have another point (-4, -2) on the line.
Plotting the two points (-1, 0) and (-4, -2), we can draw a straight line passing through them.
Here is the graph of the line:
Graph the line with the given point and slope.
The line through (-1,0) with slope 2/3
1 answer