To graph the line through (-2, 1) with a slope of 4/5, we can use the slope-intercept form of a linear equation, which is:
y = mx + b
Where m is the slope and b is the y-intercept.
In this case, the slope is 4/5, so our equation becomes:
y = (4/5)x + b
To find b, we can substitute the coordinates (-2, 1) into the equation and solve for b:
1 = (4/5)(-2) + b
1 = -8/5 + b
1 + 8/5 = b
13/5 = b
So, the equation of the line becomes:
y = (4/5)x + 13/5
To find the y-intercept, we use b = 13/5, which means the line intersects the y-axis at the point (0, 13/5).
Now, we can plot these two points on the graph and draw a line connecting them.
Here is the graph of the line through (-2, 1) with a slope of 4/5:
Graph:
-5 | .
| .
| .
| .
| .
| .
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-2 0 2 4 6
So the two coordinates on the graph are (-2, 1) and (0, 13/5).
Graph the line with the given point and slope. Find the two coordinates on a graph.
The line through (-2, 1) with slope 4/5.
1 answer