To find the ordered pairs for the given function \(y = 5(14^x)\), we will calculate the y-values for the specified x-values: -2, -1, 0, and 1.
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For \(x = -2\): \[ y = 5(14^{-2}) = 5 \left(\frac{1}{14^2}\right) = 5 \left(\frac{1}{196}\right) \approx 0.02551 \]
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For \(x = -1\): \[ y = 5(14^{-1}) = 5 \left(\frac{1}{14}\right) \approx 5 \times 0.07143 \approx 0.35714 \]
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For \(x = 0\): \[ y = 5(14^0) = 5 \cdot 1 = 5 \]
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For \(x = 1\): \[ y = 5(14^1) = 5 \cdot 14 = 70 \]
Now we can form the ordered pairs:
- For \(x = -2\), \(y \approx 0.02551\)
- For \(x = -1\), \(y \approx 0.35714\)
- For \(x = 0\), \(y = 5\)
- For \(x = 1\), \(y = 70\)
Thus, the ordered pairs are approximately:
\[ (-2, 0.02551), (-1, 0.35714), (0, 5), (1, 70) \]
Looking at the provided options, none of them appears to match these calculated values. The pairs calculated here show that the outputs are much larger than those listed in any response. Please double-check the function or the options provided.