To complete the ordered pairs for the function \( y = 5(1/4)^x \), we need to find the corresponding \( y \)-values for the given \( x \)-values: \(-2\), \(0\), and \(1\).
-
For \( x = -2 \): \[ y = 5(1/4)^{-2} = 5 \cdot (4/1)^2 = 5 \cdot 16 = 80 \]
-
For \( x = 0 \): \[ y = 5(1/4)^0 = 5 \cdot 1 = 5 \]
-
For \( x = 1 \): \[ y = 5(1/4)^1 = 5 \cdot (1/4) = 5/4 = 1.25 \]
Now we can compile the ordered pairs:
- For \( x = -2 \), \( y = 80 \): \((-2, 80)\)
- For \( x = 0 \), \( y = 5 \): \((0, 5)\)
- For \( x = 1 \), \( y = 1.25 \): \((1, 1.25)\)
Thus, the complete ordered pairs are: \((-2, 80)\), \((0, 5)\), and \((1, 1.25)\).
The correct answer is: (-2, 80), (0, 5), and (1, 1.25).