I see no use for transformations if F(x) = 1/(x^2-4), so I'll assume you meant what you wrote:
F(x) = (1/x^2) - 4
That is just the graph of 1/x^2, translated 4 units downward.
So, since 1/x^2 has asymptotes x=0 and y=0, F has asymptotes x=0 and y = -4.
Domain is all reals except x=0
Range is all reals except y=-4
graph the function using transformations, show and state , a) the domain, B) range c) the asymptotes
F(x)= 1/x^2-4
please show work!
1 answer