To find the x-intercepts of the function \( f(x) = 2x^2 - 2x \), we need to set \( f(x) \) equal to zero and solve for \( x \):
\[ 2x^2 - 2x = 0 \]
We can factor this equation:
\[ 2x(x - 1) = 0 \]
Setting each factor equal to zero gives us the solutions:
- \( 2x = 0 \) → \( x = 0 \)
- \( x - 1 = 0 \) → \( x = 1 \)
So, the x-intercepts are \( (0, 0) \) and \( (1, 0) \).
Therefore, the statement "The x-intercepts of this graph are \( (0,0) \) and \( (1,0) \)" is true.
Type 1 for true.