Asked by Kyle
Graph the function f(x)=2x^2-2x What is the Y value that corresponds to the x value -1?
What do I do first? Do I get rid off the sq fist?
What do I do first? Do I get rid off the sq fist?
Answers
Answered by
Kyle
Ohh so it is just substitution. Ok. Thanks a million!
Answered by
GPT-4o mini
To find the \( y \) value that corresponds to the \( x \) value of \(-1\) in the function \( f(x) = 2x^2 - 2x \), you don't need to get rid of the square first. Instead, you can directly substitute \(-1\) for \( x \) in the function and then evaluate it.
Here's how to do it step by step:
1. **Substitute \( x \) with \(-1\)** in the function:
\[
f(-1) = 2(-1)^2 - 2(-1)
\]
2. **Calculate \( (-1)^2 \)**:
\[
(-1)^2 = 1
\]
3. **Multiply by the coefficient:**
\[
f(-1) = 2(1) - 2(-1)
\]
\[
f(-1) = 2 - (-2)
\]
4. **Recognize that subtracting a negative is the same as adding:**
\[
f(-1) = 2 + 2
\]
\[
f(-1) = 4
\]
Therefore, the \( y \) value that corresponds to the \( x \) value of \(-1\) in the function \( f(x) = 2x^2 - 2x \) is \( 4 \).
Here's how to do it step by step:
1. **Substitute \( x \) with \(-1\)** in the function:
\[
f(-1) = 2(-1)^2 - 2(-1)
\]
2. **Calculate \( (-1)^2 \)**:
\[
(-1)^2 = 1
\]
3. **Multiply by the coefficient:**
\[
f(-1) = 2(1) - 2(-1)
\]
\[
f(-1) = 2 - (-2)
\]
4. **Recognize that subtracting a negative is the same as adding:**
\[
f(-1) = 2 + 2
\]
\[
f(-1) = 4
\]
Therefore, the \( y \) value that corresponds to the \( x \) value of \(-1\) in the function \( f(x) = 2x^2 - 2x \) is \( 4 \).
Answered by
GPT-4o mini
You're welcome! Yes, substitution is the key when evaluating a function at a specific value. If you have any more questions about functions or anything else, feel free to ask. Happy learning!