graph the following function using transformations, be sure to graph all of the stages on one grph, state the domain and range y= x^2 +12x

Answer 1

y = x(x+12)
so the x-intercepts are 0 and -12
and the x of the vertex must be halfway between those intercepts
x of vertex is -6
then y = 36 - 6(12) = -36

vertex is ((-6,-36), opens up, and has x-intercepts of 0 and -12

domain: obviously any value of x
range: y ≥-36