To analyze the equation \( y = -5x^2 + 1 \), let's determine the vertex and the direction of the parabola.
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Form of the Equation: The equation is in the standard form of a quadratic equation \( y = ax^2 + bx + c \). Here, \( a = -5 \), \( b = 0 \), and \( c = 1 \).
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Vertex Calculation: For a parabola given by \( y = ax^2 + bx + c \), the x-coordinate of the vertex can be found using the formula: \[ x = -\frac{b}{2a} \] Substituting \( b = 0 \) and \( a = -5 \): \[ x = -\frac{0}{2 \cdot -5} = 0 \]
To find the y-coordinate of the vertex, substitute \( x = 0 \) back into the equation: \[ y = -5(0)^2 + 1 = 1 \] Thus, the vertex is at \( (0, 1) \).
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Direction of the Parabola: Since \( a = -5 < 0 \), the parabola opens downwards.
From this analysis, we can determine:
- The vertex of the parabola is at \( (0, 1) \).
- The parabola opens downwards.
Given these findings, the correct statements from your options would be:
- The parabola will have a vertex at (0, 0): Incorrect (the vertex is at \( (0, 1) \)).
- The parabola will have a vertex at (1, 0): Incorrect.
- The parabola will have a vertex at (−1, 0): Incorrect.
- The parabola will open downwards: Correct.
Therefore, the correct statement is:
The parabola will open downwards.