The equation given is \( y = -5(x)^2 + 1 \). This represents a downward-opening parabola because the coefficient of \( x^2 \) is negative.
To find the vertex of the parabola, we can use the standard form of a quadratic equation, which is \( y = a(x - h)^2 + k \), where \( (h, k) \) is the vertex of the parabola. In your equation, the vertex can be identified as follows:
- The term \( -5(x)^2 \) indicates that the parabola is centered at \( x = 0 \) (since there is no horizontal shift).
- The maximum value (the y-coordinate of the vertex) occurs when \( x = 0 \):
\[ y = -5(0)^2 + 1 = 1 \]
Thus, the vertex of the parabola is located at \( (0, 1) \).
Given the options, the correct statements regarding the graph of the parabola are:
- The parabola will open downwards.
- The parabola will have a vertex at \((0, 1)\).
Therefore, the correct statement about the graph is:
The parabola will open downwards.