To analyze the equation \( y = -5x^2 + 1 \), we can identify the key features of the parabola it represents.
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Vertex: The equation is in the form \( y = ax^2 + bx + c \), which indicates a parabola. The coefficient \( a = -5 \) shows that it opens downwards. The vertex for this standard form can be found using the formula \( x = -\frac{b}{2a} \). Here, \( b = 0 \) (since there is no \( bx \) term) and \( a = -5 \):
\[ x = -\frac{0}{2(-5)} = 0 \]
Plugging \( x = 0 \) back into the equation to find the y-coordinate of the vertex:
\[ y = -5(0)^2 + 1 = 1 \]
Thus, the vertex of the parabola is at \( (0, 1) \).
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Direction: The coefficient of \( x^2 \) is negative (\( -5 \)), indicating that the parabola opens downwards.
Now, we can examine the statements provided:
- The parabola will have a vertex at \( (1,0) \). (Incorrect)
- The parabola will have a vertex at \( (0,0) \). (Incorrect)
- The parabola will open downwards. (Correct)
- The parabola will have a vertex at \( (-1,0) \). (Incorrect)
Correct Statement:
- The correct statement about the graph is: The parabola will open downwards.