To analyze the quadratic equation \(y = -5x^2 + 1\), we can identify its key features.
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Direction of the Parabola: The coefficient of \(x^2\) is \(-5\), which is negative. This means the parabola opens downward.
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Vertex of the Parabola: The general form of a quadratic equation is \(y = ax^2 + bx + c\). Here, \(a = -5\), \(b = 0\), and \(c = 1\). The vertex can be found using the formula \(x = -\frac{b}{2a}\). Substituting in the values:
\[ x = -\frac{0}{2 \cdot -5} = 0 \]
To find the y-coordinate of the vertex, substitute \(x = 0\) back into the equation:
\[ y = -5(0)^2 + 1 = 1 \]
So, the vertex is at \((0, 1)\).
Based on this analysis, we conclude that:
- The parabola indeed opens downwards.
- The vertex is at \((0, 1)\), not any of the points given in the options (including \( (−1,0) \), \( (1,0) \), or \( (0,0) \) ).
Thus, the correct response is:
The parabola will open downwards.