To graph the equation 9 - x = (3/2)y using slope-intercept form, we need to rearrange the equation to isolate y.
Starting with:
9 - x = (3/2)y
We can multiply both sides of the equation by 2/3 to isolate y:
(2/3)(9 - x) = (2/3)(3/2)y
(2/3)(9) - (2/3)(x) = (2/3)(3/2)y
6 - (2/3)x = (1/2)y
Now we can rewrite the equation in slope-intercept form y = mx + b, where m is the slope and b is the y-intercept:
y = (1/2)y + 6 - (2/3)x
Rearranging the terms, we get:
y - (1/2)y = 6 - (2/3)x
(1/2)y = (2/3)x + 6
Multiplying through by 2, we have:
y = (4/3)x + 12
Now we can graph the equation y = (4/3)x + 12.
To graph the equation, plot the y-intercept at (0, 12). The slope of the line is 4/3, which means for every 3 units moved to the right, the line moves up 4 units.
Plot a second point on the line by moving 3 units to the right and 4 units up from the y-intercept. This point is at (3, 16).
Draw a straight line through these two points to represent the equation y = (4/3)x + 12.
The graph of the equation 9 - x = (3/2)y is a straight line with a slope of 4/3 and a y-intercept of 12.
Graph the equation 9 - x = 3/2y using slope intercept form!
1 answer