To graph the equation \(2x - y = 4\) using the slope-intercept form \(y = mx + b\), we first need to rearrange the equation into that form.
Starting with the original equation:
\[2x - y = 4\]
We can isolate \(y\) by adding \(y\) to both sides and subtracting 4:
\[y = 2x - 4\]
Now we can see that the slope \(m\) is 2 and the y-intercept \(b\) is -4. This tells us that the line will cross the y-axis at (0, -4).
Next, we can find another point by selecting a value for \(x\). For example, if we let \(x = 1\):
\[ y = 2(1) - 4 = 2 - 4 = -2 \]
So another point on the line is (1, -2).
To summarize, we have two points to plot: (0, -4) and (1, -2). The line will rise as it proceeds to the right because the slope is positive.
Now let's examine the responses:
- Option a: (0, -4) and (1, 2) - Incorrect because the second point is wrong.
- Option b: (0, 1) and (-2, -2) - Incorrect because both points do not satisfy our line.
- Option c: (0, -4) and (1, -2) - Correct match to our line.
- Option d: (0, -3) and (1, -1) - Incorrect because the points do not match.
Thus, the correct response that represents the graph of the equation \(2x - y = 4\) is:
c. An illustration shows a coordinate plane with four quadrants. The x and y axes range from negative 10 to 10 in one unit increments. An upward slanting line is graphed on the coordinate plane. The upward slanting line passes through closed points plotted at (0, -4) and (1, -2).