In a directly proportional relationship, if you have a point (12, 1), it means that when the number of cups of rice is 12, the amount of water is 1. The proportional relationship can be expressed as \( y = kx \), where \( k \) is the constant of proportionality.
To find \( k \):
- We can rearrange the equation using our given point:
\[ k = \frac{y}{x} = \frac{1}{12} \]
Now we can use this relationship to identify another point on the graph. We can pick any value for \( x \) and calculate \( y \) using the equation \( y = \frac{1}{12} x \).
Let's check the provided options:
-
For \( (1/4, 2) \):
\( y = \frac{1}{12} \cdot \frac{1}{4} = \frac{1}{48} \) (not equal to 2) -
For \( (3/2, 3) \):
\( y = \frac{1}{12} \cdot \frac{3}{2} = \frac{3}{24} = \frac{1}{8} \) (not equal to 3) -
For \( (2/3, 4) \):
\( y = \frac{1}{12} \cdot \frac{2}{3} = \frac{2}{36} = \frac{1}{18} \) (not equal to 4) -
For \( (2, 6) \):
\( y = \frac{1}{12} \cdot 2 = \frac{2}{12} = \frac{1}{6} \) (not equal to 6)
Since none of the answer options fit with the proportional relationship correctly, it seems we must derive a point using the constant of proportionality k. Let's create a valid coordinate using \( k = \frac{1}{12} \):
- If \( x = 12 \), then \( y = 1 \).
- If we multiply both \( x \) and \( y \) in the ratio (which preserves the proportion), we can find valid points.
For example, if you double both:
- \( x = 24 \) and \( y = 2 \).
However, it appears that none of your suggested answers are correctly represented based on the earlier calculation. Generally, you would be looking for a point that maintains the ratio of \( \frac{1}{12} \).
In conclusion, if we want another point that fits correctly into \( y = \frac{1}{12}x \) note the values and find combinations that make sense or work proportionally from the base. If there was an oversight or missing data, please verify the question's provided points.
To summarize, you may create valid options or revisit the asked points, as currently provided points do not follow proportional derivation correctly.