To graph a line that contains the point (-6, 1) and has a slope of 5, we can use the point-slope form of a linear equation.
The point-slope form is given by:
y - y1 = m(x - x1)
Where (x1, y1) is the given point and m is the slope.
Substituting the given values into the equation, we have:
y - 1 = 5(x - (-6))
y - 1 = 5(x + 6)
y - 1 = 5x + 30
y = 5x + 31
Now we have the equation of the line in slope-intercept form (y = mx + b), where m is the slope (5) and b is the y-intercept (31).
To graph the line, we can plot the given point (-6, 1) and use the slope (5) to find additional points on the line.
Starting with the given point (-6, 1), we can move 1 unit up and 5 units to the right to find another point. This gives us the point (-1, 6).
Plotting these two points on a coordinate plane and connecting them with a straight line, we get the graph of the line y = 5x + 31:
{{{ graph( 500, 500, -10, 10, -10, 40, 5x + 31) }}}
Graph a line that contains the point
(−6,1) (−6,1)left parenthesis, minus, 6, comma, 1, right parenthesis and has a slope of
5
55.
1 answer
1 answer