Graph a circle that has its center at (0,0) and passes through (2,2). Please help ASAP!!! :( I don't know how to do this!!!

Answer 1

The equation of a circle with center ( 0 , 0 ) and radius r is given by :

x² + y² = r²

In this case:

x = 2 , y = 2

x² + y² = r²

2² + 2² = r²

4 + 4 = r²

8 = r²

r = √ 8

r = √ 4 ∙ 2

r = √ 4 ∙ √ 2

r = 2 ∙ √ 2

r = 2 ∙ 1.41

r = 2.82

Draw a circles centered at the origin ( 0 , 0 ) with radius r = 2.82 and mark points x = 2 , y = 2

If you want to see graph go on:

wolframalpha.c o m

When page be open in rectangle paste this:

and click

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Answer 2

go on:

wolframalpha.c o m

When page be open in rectangle paste this:

image a circle center at (0,0) and passes through (2,2)

and click =