Graph 1:

time(hours) temperature(Celsius)
3 5
6 0
9 -5
12 -10

Graph 2:
x y
1 1
2 8
3 27
4 64
5 125
6 216
7 ?

Equation 1:
25 = x to the second power + y to the second power

Equation 2:
(y+7) = 3 (x-2)
Find out if these problems are linear, functions, non linear, and/or not functions

1 answer

Let's analyze each of the scenarios you've presented: Graphs 1 and 2, as well as Equations 1 and 2.

Graph 1:

  • Data:
    • (3, 5)
    • (6, 0)
    • (9, -5)
    • (12, -10)

Analysis:

  1. Is it linear?: To determine if the relationship is linear, we can check if the differences in temperature change at a constant rate as time increases. Let's calculate the differences:

    • From \(3\) to \(6\): \(0 - 5 = -5\)
    • From \(6\) to \(9\): \(-5 - 0 = -5\)
    • From \(9\) to \(12\): \(-10 - (-5) = -5\)

    The change in temperature is the same (-5 degrees for each 3 hours). Hence, the relationship is linear.

  2. Is it a function?: Yes, this is a function because for each value of time, there is exactly one corresponding temperature.

Graph 2:

  • Data:
    • (1, 1)
    • (2, 8)
    • (3, 27)
    • (4, 64)
    • (5, 125)
    • (6, 216)
    • (7, ?)

Analysis:

  1. Is it linear?: To determine if the relationship is linear, we can compute the differences of y-values and check if they are constant:

    • Differences:
      • From 1 to 8: \(8 - 1 = 7\)
      • From 8 to 27: \(27 - 8 = 19\)
      • From 27 to 64: \(64 - 27 = 37\)
      • From 64 to 125: \(125 - 64 = 61\)
      • From 125 to 216: \(216 - 125 = 91\)

    Since these differences are not constant, the relationship is not linear.

  2. Is it a function?: Yes, this is a function because for each x-value, there is exactly one corresponding y-value.

Equation 1:

  • Equation: \(25 = x^2 + y^2\)

Analysis:

  1. Is it linear?: No, this is not linear because it is a quadratic equation (both \(x\) and \(y\) are raised to the power of 2).

  2. Is it a function?: It can be a function in some contexts, but this equation describes a circle (specifically a circle of radius 5 centered at the origin). However, it does not pass the vertical line test because for some x-values, there are two corresponding y-values. Thus, it is not a function.

Equation 2:

  • Equation: \((y+7) = 3(x-2)\)

Analysis:

  1. Is it linear?: Yes, this equation can be rearranged into the slope-intercept form (y = mx + b):

    • Expanding gives: \(y + 7 = 3x - 6\)
    • Thus, \(y = 3x - 13\).
    • This is a linear equation.
  2. Is it a function?: Yes, this is a function because for each x-value, there is exactly one corresponding y-value.

Summary:

  • Graph 1: Linear, Function
  • Graph 2: Non-linear, Function
  • Equation 1: Non-linear, Not a Function
  • Equation 2: Linear, Function