To solve the equation \( 49x^2 - 225 = 0 \) using the difference of squares pattern, we start by rewriting the equation:
\[ 49x^2 - 225 = 0 \]
This can be recognized as a difference of squares:
\[ (7x)^2 - 15^2 = 0 \]
We can factor this as:
\[ (7x - 15)(7x + 15) = 0 \]
Setting each factor equal to zero gives us:
- \( 7x - 15 = 0 \)
- \( 7x + 15 = 0 \)
Solving these equations:
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For \( 7x - 15 = 0 \): \[ 7x = 15 \quad \Rightarrow \quad x = \frac{15}{7} \]
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For \( 7x + 15 = 0 \): \[ 7x = -15 \quad \Rightarrow \quad x = -\frac{15}{7} \]
Thus, the correct solutions are:
\[ x = -\frac{15}{7}, \quad x = \frac{15}{7} \]
Therefore, the correct response from the options provided is:
x equals negative Start Fraction 15 over 7 End Fraction , x equals Start Fraction 15 over 7 End Fraction.