Granite has a specific heat of 800. J/g∙°C. What mass of granite is needed to store 1.50 x 10 6J of heat if the temperature of the granite is to be increased by 15.5°C?

Answer 1

To calculate the mass of granite needed to store 1.50 x 10^6 J of heat, we can use the formula:

Q = mcΔT

Where:
Q is the heat energy (in J)
m is the mass (in g)
c is the specific heat (in J/g°C)
ΔT is the change in temperature (in °C)

Plugging in the given values:
1.50 x 10^6 J = m * 800 J/g°C * 15.5°C

Simplifying the equation:
1.50 x 10^6 J = m * 12400 J/g
Divide both sides of the equation by 12400 J/g:
m = (1.50 x 10^6 J) / (12400 J/g)

Calculating value:
m = 120.96875 g

Therefore, approximately 120.97 grams of granite is needed to store 1.50 x 10^6 J of heat when the temperature of the granite is increased by 15.5°C.