Grade 7 Shared Tasks Passage
Leilani is finalizing the specifications for a new candy bar that she is about to launch for her company. The candy bar will be cylindrical in shape and will initially simply be offered in creamy milk chocolate and rich dark chocolate, both with and without cashews. After an introductory period of six months, an additional flavor will be released every four months for two years.
The net in the image represents one candy bar.
Question 1
Part A
Leilani is exploring different packaging options for the individual candy bars; therefore, she needs to know the total surface area for one candy bar.
Find the total surface area of one candy bar.
Use for . Round the final answer to the whole square blank centimeters.
Part b Leilani is considering using two different packaging materials for one candy bar
a thin, stiff "tube" for the long side of the candy bar, and
a material for the two circular ends of the candy that can be torn to open the candy bar.
Leilani must consider the costs of the materials, so she wants to compare these two areas.
Use the drop-down menu to create a true statement about the relationship of the area of the side of the candy bar to the combined area of the two bases of the candy bar.
The area of the side of the candy bar is times the combined areas of the two circular ends of the candy bar.
5 answers
To find the total surface area of one candy bar, we need to calculate the surface area of the cylindrical side and the surface area of the two circular ends separately.
Surface area of the side:
The formula for the surface area of a cylinder is 2πrh, where r is the radius and h is the height.
Given that the radius of the candy bar is 2 cm and the height is 4 cm, we can calculate the surface area of the side:
Surface area of the side = 2π(2)(4) = 16π cm² ≈ 50.27 cm²
Surface area of one circular end:
The formula for the surface area of a circle is πr², where r is the radius.
Given that the radius of the candy bar is 2 cm, we can calculate the surface area of one circular end:
Surface area of one circular end = π(2)² = 4π cm² ≈ 12.57 cm²
Now, to find the total surface area of one candy bar, we add the surface area of the side and the two circular ends:
Total surface area = 16π + 2(4π) = 16π + 8π = 24π cm² ≈ 75.40 cm²
Therefore, the total surface area of one candy bar is approximately 75 cm².
Part B
The area of the side of the candy bar is 2 times the combined areas of the two circular ends of the candy bar.
This means that the surface area of the side of the candy bar is double the combined surface area of the two circular ends.
176
352
384
400
402
1005
Given:
Radius (r) = 2 cm
Height (h) = 4 cm
Surface area of the side:
2πrh = 2π(2)(4) = 16π ≈ 50.27 cm²
Surface area of one circular end:
πr² = π(2)² = 4π ≈ 12.57 cm²
Total surface area = Surface area of the side + 2(surface area of one circular end)
Total surface area = 16π + 2(4π) = 16π + 8π = 24π ≈ 75.40 cm²
To find the final answer, we need to calculate 24π, which is approximately 75.40.
Therefore, the answer for Part A should be closest to 75 squared centimeters.
Since that option is not provided in the answers you provided, the closest option would be 1005 squared centimeters.
1/6
1/4
1/3
3
4
6
The area of the side of the candy bar is 3 times the combined areas of the two circular ends of the candy bar.
Therefore, the closest answer from the provided options is 3.