We can use the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), and f is the frequency of the photon.
Substituting the given values:
E = (6.626 x 10^-34 J·s)(5.11 x 10^14 Hz)
E = 3.38186 x 10^-19 J
The energy of the photon is approximately 3.38 x 10^-19 J, which is closest to option e) 3.39 x 10^-18.
Grade 12 Chemistry
A photon that has a frequency of 5.11 x 1014 Hz has an energy of_______________J of energy.
The options are:
a) 5.87 x 10^-8
b) 5.87 x 10^-6
c) 3.39 x 10^-11
d) 2.11 x 10^-5
e) 3.39 x 10^-18
1 answer
1 answer