I suspect that the distance was either
200m or 2.00*10^2m
If that's so, then the acceleration
a = ∆v/t = 10/t
the distance is
s = 20t + 1/2 at^2 = 20t + 5t = 25t = 200
so, t = 8s
I think it should be easy now to answer the questions.
GP. A speedboat increases it's speed uniformly from V1=20.0m/s to Vf=30.0m/s in a distance of 200X10^2m. (a) Draw a coordinate system for this situation and label the relevant quantities, including vectors. (b) For the given information, what single equation is most appropriate for finding the acceleration? (c) Solve the equation selected in part (b) symbolically for the boat's acceleration in terms of Vf,V1, and delta x. (d) Substitute given values, obtaining that acceleration. (e) Find the time it takes the boat to travel the given distance.
2 answers
University hargeisa