2Al + 3FeO ==> 3Fe + Al2O3
You have 13.2 mol FeO. Use the coefficients in the balanced equation to convert mols of what you want.
13.2 mol Al x (2 mol Al/3 mols FeO) = 13.2 x 2/3 = 8.8 and you answer is correct; however, I don't like the way you got there. If I do your math I see
13.2/3*2 = 13.2/6 = 2.2. Actually, you meant to write [13.2/3]*2 or 13.2 x 2/3.
For equations you need to find the caps key and use it. Technically, your equation means nothing to me. Co is cobalt, CO is carbon monoxide, and co is the abbreviation for company so it makes a difference in what you're trying to say.
2Na + 2H2O ==> 2NaOH + H2
1. Write and balance the equation. You've done that.
2. Convert what you have (13.5 g Na) to mols. mol = grams/atomic mass = ?
3. Using the coefficients (as in the previous problem) to convert mols of what you have (in this case Na) to mols mols of what you wnt (in this case H2).
4. Now convert mols H2 to units you want. In this case you want volume so
a. mols H2 x 22.4 L/mol = ? L H2.
b. Some problems ask for grams. In that case, then mols H2 x molar mass H2 = g H2.
Print this procedure out. It will work ALL of your simple stoichiometry problems. It will not do limiting reagent problems with with a tweak or two it will.
Good morning. I need help solving 2 problems for chemistry. For #1 I need someone to check my work and tell me if I did it wrong and show me how and where I went wrong. And for #2 I need someone to help me figure out how to solve it and explain.
1. With the balanced equation below:
2Al+3FeO—>3Fe+Al2O3
Calculate the moles of aluminum that are needed to react completely with 13.2 moles of FeO
[My answer/work]
FeO: Al
3:2
13.2 divides by 3 x 2 =8.8
(I’m not sure if I’m correct or not but can someone help me.)
2. Sodium and water react according to the equation if 13.5g of sodium are added to excess water how many liters of hydrogen gas are formed at stp 2na+2h2o—>2naoh+h2
(I mainly need help solving this one. Can someone please help me)
1 answer
3 answers